Re: SELECT DISTINCT ... ORDER BY problem

Grzegorz Jaśkiewicz wrote:
> On Mon, Dec 8, 2008 at 10:19 PM, Madison Kelly <linux@alteeve.com> wrote:
>> Hi all,
>>
>>  I've got a table that I am trying to SELECT DISTINCT on one column and
>> ORDER BY on a second column, but am getting the error:
>>
>> SELECT DISTINCT ON expressions must match initial ORDER BY expressions
>
> try
> SELECT distinct,  array_accum(bar) FROM table WHERE bar < '2008-12-07
>  16:32:46' AND tbl_id=153 ORDER BY bar LIMIT 1;
>
> or even, when you change bar to proper type - that is, timestamp
>
> SELECT distinct foo,  min(bar) as minbar, max(bar) as maxbar FROM
> table WHERE bar < '2008-12-07
>  16:32:46' AND tbl_id=153 ORDER BY bar LIMIT 1;
>
> etc.
>
> Trick, is to use aggregate on other value(s).
>
> HTH

Well shoot, I didn't realize I had the 'text' where I should have used
'timestamp'. >_<

I updated the column, but it took me some fiddling (on a test box!) to
sort out the proper command. In case it helps someone else, here was the
error I was getting when I tried ALTER without USING:

ALTER TABLE table ALTER foo TYPE TIMESTAMP WITHOUT TIME ZONE;
ERROR:  column "foo" cannot be cast to type "pg_catalog.timestamp"

The syntax I needed was:

ALTER TABLE table ALTER foo TYPE TIMESTAMP WITHOUT TIME ZONE USING CAST
(foo AS TIMESTAMP);

I know it's a little off-topic, but maybe it'll help someone searching
someday. :)

When I try to use:

SELECT distinct foo,  min(bar) as minbar, max(bar) as maxbar FROM table
WHERE bar < '2008-12-07 16:32:46' AND tbl_id=153 ORDER BY bar LIMIT 1;

I get the error:

ERROR:  column "table.foo" must appear in the GROUP BY clause or be used
in an aggregate function

Already a very big help though, thanks!

Madi