SELECT DISTINCT ... ORDER BY problem
От | Madison Kelly |
---|---|
Тема | SELECT DISTINCT ... ORDER BY problem |
Дата | |
Msg-id | 493D9D55.6080904@alteeve.com обсуждение исходный текст |
Ответы |
Re: SELECT DISTINCT ... ORDER BY problem
Re: SELECT DISTINCT ... ORDER BY problem |
Список | pgsql-general |
Hi all, I've got a table that I am trying to SELECT DISTINCT on one column and ORDER BY on a second column, but am getting the error: SELECT DISTINCT ON expressions must match initial ORDER BY expressions I can't add the second column to the DISTINCT clause because every row is unique. Likewise, I can't add the first column to my ORDER BY as it'd not sort the way I need it to. Here is a simplified version of my query: \d table Table "table" Column | Type | Modifiers -----------------+---------+------------------------------------------------ tbl_id | integer | not null default nextval('tbl_seq'::regclass) foo | text | bar | text | SELECT DISTINCT ON (foo) foo, bar FROM table WHERE bar < '2008-12-07 16:32:46' AND tbl_id=153 ORDER BY bar LIMIT 1; I understand from: http://archives.postgresql.org/pgsql-sql/2007-02/msg00169.php That this is not really possible because the any given 'foo' column could match multiple 'bar' columns, so what do you search by? However, it's made some sort of decision as a value is shown in 'bar' for each 'foo'. So my question is two-fold: 1. Can I not say, somehow, "sort all results by 'bar', and return the first/last 'bar' for each distinct 'foo'? 2. Can I somehow say "Order the results using the value of 'bar' you return, regardless of where it came from"? Thanks all! Madi
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