Speed difference between select ... union select ... and select from partitioned_table
От | Pablo Alcaraz |
---|---|
Тема | Speed difference between select ... union select ... and select from partitioned_table |
Дата | |
Msg-id | 47225014.5040101@laotraesquina.com.ar обсуждение исходный текст |
Ответы |
Re: Speed difference between select ... union select ...
and select from partitioned_table
Re: Speed difference between select ... union select ... and select from partitioned_table Re: Speed difference between select ... union select ... and select from partitioned_table Re: Speed difference between select ... union select ... and select from partitioned_table |
Список | pgsql-performance |
Hi List! I executed 2 equivalents queries. The first one uses a union structure. The second uses a partitioned table. The tables are the same with 30 millions of rows each one and the returned rows are the same. But the union query perform faster than the partitioned query. My question is: why? :) [pabloa@igor testeo]$ cat query-union.sql select e, p, sum( c) as c from ( select e, p, count( *) as c from tt_00003 group by e, p union select e, p, count( *) as c from tt_00006 group by e, p union select e, p, count( *) as c from tt_00009 group by e, p union select e, p, count( *) as c from tt_00012 group by e, p union select e, p, count( *) as c from tt_00015 group by e, p ) as t group by e, p order by e, p desc; [pabloa@igor testeo]$ cat query-heritage.sql select e, p, count( *) as c from tt group by e, p order by e, p desc; The server is a Athlon 64x2 6000+ 2 Gb RAM PostreSQL 8.2.5 The structure tables are: CREATE TABLE tt_00003 ( -- Inherited: idtt bigint NOT NULL, -- Inherited: idttp bigint NOT NULL, -- Inherited: e integer NOT NULL, -- Inherited: dmodi timestamp without time zone NOT NULL DEFAULT now(), -- Inherited: p integer NOT NULL DEFAULT 0, -- Inherited: m text NOT NULL, CONSTRAINT tt_00003_pkey PRIMARY KEY (idtt), CONSTRAINT tt_00003_idtt_check CHECK (idtt >= 1::bigint AND idtt <= 30000000::bigint) ) INHERITS (tt) WITHOUT OIDS; ALTER TABLE tt_00003 ; CREATE INDEX tt_00003_e ON tt_00003 USING btree (e);
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