Re: Auto Partitioning
От | Markus Schiltknecht |
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Тема | Re: Auto Partitioning |
Дата | |
Msg-id | 4613BB72.1090602@bluegap.ch обсуждение исходный текст |
Ответ на | Re: Auto Partitioning (Gregory Stark <stark@enterprisedb.com>) |
Ответы |
Re: Auto Partitioning
Re: Auto Partitioning |
Список | pgsql-hackers |
Hi, Gregory Stark wrote: > Put another way, multi-table indexes defeat the whole purpose of having > partitioned the table in the first place. If you could have managed a single > massive index then you wouldn't have bothered partitioning. That depends very much on the implementation of the multi-table index, as you describe below. I think the major missing part is not *how* such a meta-index should work - it's easily understandable, that one could use the per-table indices - but a programming interface, similar to the current index scan or sequential scan facility, which could return a table and tuple pointer, no? > However there is a use case that can be handled by a kind of compromise index. > Indexes that have leading columns which restrict all subtrees under that point > to a single partition can be handled by a kind of meta-index. So you have one > index which just points you to the right partition and corresponding index. Yeah. > That lets you enforce unique constraints as long as the partition key is part > of the unique constraint. Is that already sufficient? That would alter the ordering of the columns in the index, no? I mean: CREATE INDEX x ON test(a, b, c); isn't the same as CRETAE INDEX x ON test(c, b, a); That's why I'd say, the first column of an index would have to be equal to all of the columns used in the partitioning key. Regards Markus
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