Re: Any advantage to integer vs stored date w. timestamp
От | Richard Huxton |
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Тема | Re: Any advantage to integer vs stored date w. timestamp |
Дата | |
Msg-id | 45EED472.2070303@archonet.com обсуждение исходный текст |
Ответ на | Re: Any advantage to integer vs stored date w. timestamp (Zoolin Lin <zoolin3g@yahoo.com>) |
Ответы |
Re: Any advantage to integer vs stored date w. timestamp
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Список | pgsql-performance |
Zoolin Lin wrote: > thanks for your reply > >> Primary table is all integers like: >> >> date id | num1 | num2 | num3 | num4 | num5 | num6 | num7 | num 8 >> ------------------------------------------------------------------------------------------------- >> primary key is on date to num->6 columns > >>> What types are num1->8? > > They are all integer Hmm - not sure if you'd get any better packing if you could make some int2 and put them next to each other. Need to test. >> date_id | date w timestamp ---------------------------------------- >> 1 | 2007-2-15 Midnight 2 | 2007-2-15 1 am 3 | >> 2007-2-15 2 am etc for 24 hours each day > >>> If you only want things accurate to an hour, you could lost the >>> join and just store it as an int: 2007021500, 2007021501 etc. > > Hmm yeh I could, I think with the amount of data in the db though it > behooves me to use one of the date types, even if via lookup table. You can always create it as a custom ZLDate type. All it really needs to be is an int with a few casts. > So I guess I'm just not sure if I'm really gaining anything by using > an integer date id column and doing a join on a date lookup table, > vs just making it a date w. timestamp column and having duplicate > dates in that column. > > I would imagine internally that the date w. timestamp is stored as > perhaps a time_t type plus some timezone information. I don't know > if it takes that much more space, or there's a significant > performance penalty in using it It's a double or int64 I believe, so allow 8 bytes instead of 4 for your int. > 2,500 rows per hour, with duplicate date columns, seems like it could > add up though. Well, let's see 2500*24*365 = 21,900,000 * 4 bytes extra = 83MB additional storage over a year. Not sure it's worth worrying about. -- Richard Huxton Archonet Ltd
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