select count of all overlapping geometries and return 0 if none.
От | Duffer Do |
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Тема | select count of all overlapping geometries and return 0 if none. |
Дата | |
Msg-id | 457532.70947.qm@web45913.mail.sp1.yahoo.com обсуждение исходный текст |
Ответы |
Re: select count of all overlapping geometries and return 0 if none.
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Список | pgsql-sql |
<table border="0" cellpadding="0" cellspacing="0"><tr><td style="font: inherit;" valign="top">Hello all,<br />I have 2 tableslocations and user_tracker:<br /><br />locations has 2 columns<br />location_name<br />location_geometry<br /><br />user_trackerhas 3 columns<br />user_name<br />user_geometry<br />user_timestamp<br /><br /><br />locations table is coordinatesand names of areas of interest.<br />user_tracker basically is an archive of a user's movements as he pans hismap.<br /><br />I have a need to assign a ranking of locations based on how many times users have intersected this location.<br/><br />The problem I am having is that my query only returns locations that have been intersected by a user.<br/>I need it to return ALL locations and a zero if this location has not been intersected.<br /><br />As an example:<br/><br />LOCATIONS<br />1: Talahassee, FL | talahassee's bounding box<br />2: Manhattan, NY | Manhattan's boundingbox<br />3: Frankfurt, GE | Frankfurt's bounding box<br /><br /><br />USER_TRACKER<br />john doe | geometrythat overlaps Frankfurt | today<br />john doe | geometry that overlaps Frankfurt | today<br />john doe | geometry that overlaps Frankfurt | today<br />john doe | geometry that overlaps Frankfurt | yesterday<br />johndoe | geometry that overlaps Frankfurt | Monday<br />john doe | geometry that overlaps Frankfurt | Sunday<br/>Mary Jane | geometry that overlaps Manhattan | today<br />Rob Roy | geometry that overlaps Manhattan | today<br/>Rob Roy | geometry that overlaps Manhattan | today<br /><br /><br />I want to return the following:<br />locations | number_visits<br />Frankfurt | 6<br />Manhattan | 3<br />Talahassee | 0<br /><br />My query onlyreturns:<br />Frankfurt | 6<br />Manhattan | 3<br /><br />Now I have really simplified this example for readability,my actual tables are more complex.<br /><br />How can I accomplish this?<br /><br />My query:<br />SELECT count(user_name)as number_visits, location_name from locations, user_tracker WHERE user_geometry && location_geometry<br/><br />Thanks in advance</td></tr></table><br />
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