Re: division by zero error in a request
От | Oisin Glynn |
---|---|
Тема | Re: division by zero error in a request |
Дата | |
Msg-id | 4537CDA7.1010107@oisinglynn.com обсуждение исходный текст |
Ответ на | division by zero error in a request (Bernard Grosperrin <bernard@bgsoftfactory.com>) |
Список | pgsql-general |
Bernard Grosperrin wrote: > I wants to make a view giving me some statistics. > > I am not sure to understand why something like this > > SELECT location_id, (sold_parts_amount_dly + sold_labor_amount_dly) / > (sold_parts_amount_dly + sold_labor_amount_dly) from sales > > give me a division by zero error? > > If that is not the way to go, should I write a function that I would call > instead? > > Thanks, > Bernard > > ---------------------------(end of broadcast)--------------------------- > TIP 6: explain analyze is your friend > If (sold_parts_amount_dly + sold_labor_amount_dly) equals zero you will get an error as you cannot divide by zero. Also in every case where (sold_parts_amount_dly + sold_labor_amount_dly) is not zero wont the answer be 1 as (sold_parts_amount_dly + sold_labor_amount_dly)/(sold_parts_amount_dly + sold_labor_amount_dly) is always 1?? To try and find the zero you could do the following: select count(*) from sales where (sold_parts_amount_dly + sold_labor_amount_dly)=0; and if that is not a staggering amount of rows select * from sales where (sold_parts_amount_dly + sold_labor_amount_dly)=0; and try and identify why this is happening if it is not expected? or if you want to ignore rows where (sold_parts_amount_dly + sold_labor_amount_dly)=0; then SELECT location_id, (sold_parts_amount_dly + sold_labor_amount_dly) / (sold_parts_amount_dly + sold_labor_amount_dly) from sales where (sold_parts_amount_dly + sold_labor_amount_dly)>0 Oisin
Вложения
В списке pgsql-general по дате отправления: