Re: Select Where using character varying ??

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От Charley Tiggs
Тема Re: Select Where using character varying ??
Дата
Msg-id 452219C8.4010200@tiggs.net
обсуждение исходный текст
Ответ на Select Where using character varying ??  ("ben wilko" <wilko_ben@hotmail.com>)
Ответы Re: Select Where using character varying ??  (DCarrero <dcarreroc@gmail.com>)
Список pgsql-php
ben wilko wrote:
> Hi Guys
>
> I am printing names into a combo box and posting the variable. I try and use the
> name ($Sem) in an SQL statement; WHERE name = $Sem; but I get an error which is
> displayed near the end of this message. Are we able compare php string to
> postgresql character varying??  not sure how else to do the selection
>
>
> $conn = pg_Connect("host=localhost dbname=#### user=#### password=####");
>    if (!$conn) {echo "An database connection error occurred.\n"; exit;}
>
>
> // e.g. $Sem = "seminar one";
>
> $Sem = $_POST['Seminars'];
>
>
> $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem");
>  if (!$SemNo) {echo "A query error occurred in retreiving the selected seminar's
> ID <br>"; /*exit;*/}
> $Sem_No = pg_Result($Sem_No, 0);
>
> // Error Message
>
> *Warning*: pg_exec() [function.pg-exec
> <http://www.citanalyst.com/jet/form/function.pg-exec>]: Query failed: ERROR:
> syntax error at or near "one" at character 54 in
> */home/bdwilko/public_html/jet/form/insertP.php* on line *56*
> A query error occurred in retreiving the selected seminar's ID
>

Make sure that you're quoting the value you want to compare.  At a quick
glance, this where the error is:

$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem");

should be:

$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name =
'$Sem'");

To be more accurate, you should probabley do:

$Sem = pg_escape ( $Sem );
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name =
'$Sem'");

Charley

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