Re: Select Where using character varying ??
От | Charley Tiggs |
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Тема | Re: Select Where using character varying ?? |
Дата | |
Msg-id | 452219C8.4010200@tiggs.net обсуждение исходный текст |
Ответ на | Select Where using character varying ?? ("ben wilko" <wilko_ben@hotmail.com>) |
Ответы |
Re: Select Where using character varying ??
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Список | pgsql-php |
ben wilko wrote: > Hi Guys > > I am printing names into a combo box and posting the variable. I try and use the > name ($Sem) in an SQL statement; WHERE name = $Sem; but I get an error which is > displayed near the end of this message. Are we able compare php string to > postgresql character varying?? not sure how else to do the selection > > > $conn = pg_Connect("host=localhost dbname=#### user=#### password=####"); > if (!$conn) {echo "An database connection error occurred.\n"; exit;} > > > // e.g. $Sem = "seminar one"; > > $Sem = $_POST['Seminars']; > > > $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem"); > if (!$SemNo) {echo "A query error occurred in retreiving the selected seminar's > ID <br>"; /*exit;*/} > $Sem_No = pg_Result($Sem_No, 0); > > // Error Message > > *Warning*: pg_exec() [function.pg-exec > <http://www.citanalyst.com/jet/form/function.pg-exec>]: Query failed: ERROR: > syntax error at or near "one" at character 54 in > */home/bdwilko/public_html/jet/form/insertP.php* on line *56* > A query error occurred in retreiving the selected seminar's ID > Make sure that you're quoting the value you want to compare. At a quick glance, this where the error is: $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem"); should be: $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = '$Sem'"); To be more accurate, you should probabley do: $Sem = pg_escape ( $Sem ); $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = '$Sem'"); Charley
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