Re: avg(interval)

Well, the query is working ok numerically, but should the answer really 
be reported as 4 days and 33 hours?

Erik

Aaron Bono wrote:
> Right, the 23 is just less than 1 day, not 23 days.
>
> The good news: your query is working!
>
> -Aaron
>
> On 6/26/06, *Joe* < dev@freedomcircle.net 
> <mailto:dev@freedomcircle.net>> wrote:
>
>     Tom Lane wrote:
>     > "Jeremiah Elliott" < geek00@gmail.com <mailto:geek00@gmail.com>>
>     writes:
>     >> however if i don't average them here is what i get:
>     >> "7 days 22:24:50.62311";"*2420"
>     >> "9 days 22:21: 02.683393";"*2420"
>     >> "23:21:35.458459";"*2420"
>     >> "4 days 22:47:41.749756";"*2420"
>     >> "3 days 06:05:59.456947";"*2420"
>     >
>     >> which should average to just over nine days -
>     >
>     > Uh ... how do you arrive at that conclusion?  I haven't done the
>     math,
>     > but by eyeball an average of four-something days doesn't look
>     out of
>     > line for those values.
>
>     It seems he's calculating (7 + 9 + 23 + 4 + 3) / 5 ...
>
>     Joe
>


-- 
erik jones <erik@myemma.com>
software development
emma(r)