Re: how to solve this problem
От | Steve Crawford |
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Тема | Re: how to solve this problem |
Дата | |
Msg-id | 443E99C5.3080800@pinpointresearch.com обсуждение исходный текст |
Ответ на | how to solve this problem (ivan marchesini <marchesini@unipg.it>) |
Ответы |
Re: how to solve this problem
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Список | pgsql-sql |
> I have a table where there are 20 columns named > vinc1, vinc2, vinc3, vinc4, etc.... > > the values contained into each column are simply 1 or 0 (each column is > dichotomic) > 1 means presence > 0 means absence > > I would obtain a column (new_column) containg the name of the columns, > comma separated, where the value is = 1 > > for example: > > vinc1 vinc2 vinc3 vinc4 new_column > 1 0 1 0 vinc1,vinc3 > 0 0 0 1 vinc4 > 0 1 1 1 vinc2,vinc3,vinc4 > > can someone help me to find the best way to obtain this result??? > thank you very much Here's a brute-force method. Maybe someone else has a more elegant way. More info on the nature of your data and what you are trying to obtain from it would help in finding such elegance. select substr( case when vinc1 = 1 then ',vinc1' else '' || case when vinc2 = 1 then ',vinc2' else '' || ... case whenvinc20 = 1 then ',vinc20' else '' ,2) as new_column ... As to the binary representation mentioned elsewhere, the idea is that you can view vinc1-vinc20 as bits in a binary number equal to vinc1 + 2*vinc2 + 4*vinc3 + 8*vinc4...2^19*vinc20. Whether or not this is useful depends on what you are trying to do. Cheers, Steve
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