Re: union with count?
От | Richard Broersma Jr |
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Тема | Re: union with count? |
Дата | |
Msg-id | 437650.83949.qm@web31809.mail.mud.yahoo.com обсуждение исходный текст |
Ответ на | union with count? (Gerardo Herzig <gherzig@fmed.uba.ar>) |
Список | pgsql-sql |
--- Gerardo Herzig <gherzig@fmed.uba.ar> wrote: > Hi dudes, i have the following question > i have 2 tables with the same format, and i want to know if is there a > possibility of using some sort of count(*) for achieving this result: > select a from table1 where (condition) union select a from table2 where > (condition), count(a) group by a I think you are showing count(a) in the wrong spot in your example. But if I understand you correctly the following should do what you want: SELECT count(a) FROM ( SELECT a FROM table1 WHERE (your_condition = true) UNION -- you can use UNION ALL if you -- want rows that are duplicates from each table. SELECT a FROM table2 WHERE (your_condition = true) ) GROUP BY a;
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