Re: Your question about date

That's a good one, but it has the disadvantage of 
giving a null result row: 
insert into test values ( '2004-12-22' ) ;
The SELECT from below gives result 
--------    31    33    25(null)    42
(5 rows)
Also, I am not sure about the order of values. 
Anyway, Béatrice, thanks for your time. 
Regards, Christoph 

Béatrice Yueksel wrote:
> 
> Dear Christoph,
> perhaps you could try something like this example.
> Regards,
> BĂŠatrice
> 
> The table:
> ----------
> # select * from test;
>     date
> ------------
>  2005-02-02
>  2005-03-05
>  2005-04-07
>  2005-05-02
> (4 rows)
> 
> The query
> ----------
> 
> SELECT
>  (( select test1.date
>            from test test1
>            where test1.date > test.date limit 1)
>    - test.date ) AS result from test;
> 
> t1.date >
> RESULT:
> -------
>  result
> --------
>      31
>      33
>      25
> 
> Am Montag, den 21.03.2005, 10:54 +0100 schrieb Christoph Haller:
> > Octavio Alvarez wrote:
> > >
> > > Sorry, I tried to make my subject as good as possible.
> >
> > Ahem, what subject?
> > >
> > > I have a table where I store the dates in which I take out of my inventory
> > > (like "installation dates")
> > >
> > > table
> > > ---------------
> > > row_id   SERIAL
> > > date     DATE
> > > fk_item  INTEGER
> > >
> > > and that's pretty much it.
> > >
> > > I want to have a query returning how long have been certain items lasting.
> > >
> > > Say I have:
> > >
> > > SELCT date FROM table WHERE fk_item = "INKJET_INK-BW"
> > >
> > > date
> > > -------------
> > > 2005-02-02
> > > 2005-03-05
> > > 2005-04-07
> > > 2005-05-02
> > >
> > > I need something to calculate the intervals between those dates, like this:
> > >
> > > intervals (in days)
> > > --------------------
> > >   31
> > >   34
> > >   25
> > >
> > > So I can get the stddev and stuff from the "duration" of the items.
> > >
> > > I've been having a hard time with it. I'm trying NOT to program new
> > > functions.
> >
> > I cannot see how this could be achieved without the use of a function.
> > But if there is a way after all, I would be interested in learning it.
> > >
> > > Any help will be appreciated.
> > >
> > > --Octavio
> > > --
> >
> > Regards, Christoph
> >