Re: UPDATE - Changing Password
От | Robby Russell |
---|---|
Тема | Re: UPDATE - Changing Password |
Дата | |
Msg-id | 4081A448.4070204@commandprompt.com обсуждение исходный текст |
Ответ на | UPDATE - Changing Password ("Yasmine Kedoo" <yazkedoo@hotmail.com>) |
Список | pgsql-php |
Yasmine Kedoo typed this on 04/17/2004 02:28 PM: > Hi. > > Does anyone know how to use UPDATE with PHP for changing a password? > I've tried the following code: > > $query = "UPDATE patperinfo SET trim(password)='$newpw' WHERE > trim(gpid)='$gpidno'"; > $result = pg_exec($database, $query); > > where new $newpw & $gpidno are the values entered into a form then > passed to the script. > > I get the following error: > > Warning: PostgreSQL query failed: ERROR: parser: parse error at or near > "(" at character 27 in /home/webpages/yamkedoo/Tests/chpw1.php on line 48 > > where the error is on the line: $result = pg_exec($database, $query); > > $query = "UPDATE tablename SET password = '$newpw' WHERE ... I don't know why you'd trim a fieldname while setting it. -Robby -- Robby Russell, | Sr. Administrator / Lead Programmer Command Prompt, Inc. | http://www.commandprompt.com rrussell@commandprompt.com | Telephone: (503) 667.4564
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