Re: [PATCH] GROUP BY ALL
От | Tom Lane |
---|---|
Тема | Re: [PATCH] GROUP BY ALL |
Дата | |
Msg-id | 4054709.1758895915@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: [PATCH] GROUP BY ALL (Peter Eisentraut <peter@eisentraut.org>) |
Ответы |
Re: [PATCH] GROUP BY ALL
Re: [PATCH] GROUP BY ALL |
Список | pgsql-hackers |
Peter Eisentraut <peter@eisentraut.org> writes: > The initially proposed patch appears to have the right idea overall. > But it does not handle more complex cases like > SELECT a, SUM(b)+a FROM t1 GROUP BY ALL; > (For explanation: GROUP BY ALL expands to all select list entries that > do not contain aggregates. So the above would expand to > SELECT a, SUM(b)+a FROM t1 GROUP BY a; > which should then be rejected based on the existing rules.) I thought I understood this definition, up till your last comment. What's invalid about that expanded query? regression=# create table t1 (a int, b int); CREATE TABLE regression=# SELECT a, SUM(b)+a FROM t1 GROUP BY a; a | ?column? ---+---------- (0 rows) regards, tom lane
В списке pgsql-hackers по дате отправления: