Re: help on to_date conversion please....

Never mind.  Just figured it out.  Need to grab the substring from 2 for 8
from the to_char result because it holds character number 1 reserv ed for +
or - signs.  + is default or white space.  I think that is the reason.  Any
other input?????

hwds=# select to_date(substring(to_char(20020101, '99999999') from 2 for
8), 'yyyymmdd');
   to_date
------------
  2002-01-01
(1 row)

At 03:13 PM 4/3/02 -0800, Chris Pesko wrote:
>I am converting an 8 digit number to a date.  I don't see a postgres
>function to do it direct, but two functions seems like I'm on the right
>track, to_char and to_date.  Individually I get them to work, but when I
>combine them I get the wrong answer.  see below.  Can anyone help in
>getting the right date from an 8 digit number input formatted as yyyymmdd?
>
>
>hwds=# select to_char(20020101, '99999999');
>   to_char
>-----------
>   20020101    CORRECT.
>(1 row)
>
>hwds=# select to_date('20020101','yyyymmdd');
>   to_date
>------------
>  2002-01-01    CORRECT.
>(1 row)
>
>hwds=# select to_date(to_char(20020101, '99999999'),'yyyymmdd');
>   to_date
>------------
>  2003-08-12     WHY DOES IT GIVE ME DIFFERENT ANSWER WHEN I COMBINE THE
> FUNCTIONS?
>(1 row)
>
>
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