Re: order of nested loop
От | Joseph Shraibman |
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Тема | Re: order of nested loop |
Дата | |
Msg-id | 3EEF50B1.9020603@selectacast.net обсуждение исходный текст |
Ответ на | Re: order of nested loop (Tom Lane <tgl@sss.pgh.pa.us>) |
Ответы |
Re: order of nested loop
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Список | pgsql-general |
Tom Lane wrote: > > That scan is estimated to yield 5446 rows and it only yields 1. Do you > have any idea why the estimate is so far off? (My guess is that podkey, > status and banned are correlated to a large extent, but you tell us.) The relationship between d and u is like this: There is a row in d for each user, and for each pod they are a member of there is an entry in u. So when I'm querying u for members of a particular pod I'm filtering by the status of the d entry and that status of the u entry. There are a lot of entries in d, but only a few of them will be members of a particular pod. Thus it would make sense to first get the entries in u, filter them, then filter by their status in d. There will be an entry in d for each entry in u, but not vice versa. The planner shows this for the scan on d: (cost=0.00..2380577.42 rows=525568 width=49) Maybe it thinks it will reach the limit of 25 before it actually does, which is why it is willing to try something so expensive?
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