Re: contrib/tablefunc/connectby question
От | Joe Conway |
---|---|
Тема | Re: contrib/tablefunc/connectby question |
Дата | |
Msg-id | 3EA56D06.1070404@joeconway.com обсуждение исходный текст |
Ответ на | contrib/tablefunc/connectby question (sector119@mail.ru) |
Список | pgsql-general |
sector119@mail.ru wrote: > how am I able to get data field? create table menu (id integer, parent_id integer, data text); insert into menu values(1,null,'root'); insert into menu values(2,1,'menu 2'); insert into menu values(3,1,'menu 3'); insert into menu values(4,2,'menu 4'); insert into menu values(5,2,'menu 5'); insert into menu values(6,4,'menu 6'); insert into menu values(7,3,'menu 7'); insert into menu values(8,6,'menu 8'); insert into menu values(9,5,'menu 9'); regression=# SELECT c.*, m.data FROM connectby('menu', 'id', 'parent_id', '1', 0, '~') AS c(id int, parent_id int, level int, branch text), menu m WHERE m.id = c.id; id | parent_id | level | branch | data ----+-----------+-------+-----------+-------- 1 | | 0 | 1 | root 2 | 1 | 1 | 1~2 | menu 2 3 | 1 | 1 | 1~3 | menu 3 4 | 2 | 2 | 1~2~4 | menu 4 5 | 2 | 2 | 1~2~5 | menu 5 6 | 4 | 3 | 1~2~4~6 | menu 6 7 | 3 | 2 | 1~3~7 | menu 7 8 | 6 | 4 | 1~2~4~6~8 | menu 8 9 | 5 | 3 | 1~2~5~9 | menu 9 (9 rows) HTH, Joe
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