Re: stored procedure

then do ( ( 6 * random() )::int ) % 6

Bruno Wolff III wrote:
> On Tue, Apr 01, 2003 at 11:26:47 -0500,
>   Peter Choe <choepete@mindspring.com> wrote:
>
>>thanks.  i just tried it out and it seems that it would generate a
>>random number between 0 and 1.  is that a valid assumption?  if that is
>>the case, how can i cast it to an int value?  i assume that there is a
>>cast function somewhere, but i can't tell by the names of the pronames.
>
>
> Normally you multiply by the range you want and then you can make a cast.
> Note however, that multiplication may cause a value to round up so that
> (6*random())::int might on very rare occasions return 6 instead of the
> expected 0, 1, 2, 3, 4 or 5. (At least on some systems.)
>
>
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