Re: SQL syntax
От | Jean-Luc Lachance |
---|---|
Тема | Re: SQL syntax |
Дата | |
Msg-id | 3D500991.78527FD5@nsd.ca обсуждение исходный текст |
Ответ на | SQL syntax (frederic massot <frederic@juliana-multimedia.com>) |
Список | pgsql-sql |
Try: Order by mod( id_mois + 12 - <current_month>, 12) frederic massot wrote: > > Hello, > > I have a table containing the months of the year : > > travail=> select * from mois order by id_mois; > > id_mois|mois_fr |mois_en |mois_de > -------+---------+---------+--------- > 1|Janvier |January |Januar > 2|Fevrier |February |Februar > 3|Mars |March |Marz > 4|Avril |April |April > 5|Mai |May |Aber > 6|Juin |June |Juni > 7|Juillet |July |Juli > 8|Aout |August |August > 9|Septembre|September|September > 10|Octobre |October |Oktober > 11|Novembre |November |November > 12|Decembre |December |Dezember > (12 rows) > > And I try to obtain for one month given (for example August : 8) two > previous months, the current month, and nine next months : > > id_mois|mois_fr |mois_en |mois_de > -------+---------+---------+--------- > 6|Juin |June |Juni > 7|Juillet |July |Juli > 8|Aout |August |August > 9|Septembre|September|September > 10|Octobre |October |Oktober > 11|Novembre |November |November > 12|Decembre |December |Dezember > 1|Janvier |January |Januar > 2|Fevrier |February |Februar > 3|Mars |March |Marz > 4|Avril |April |April > 5|Mai |May |Aber > > Do you see how making in a SQL request ? > > Thank you. > -- > ============================================== > | FREDERIC MASSOT | > | http://www.juliana-multimedia.com | > | mailto:frederic@juliana-multimedia.com | > ===========================Debian=GNU/Linux=== > > ---------------------------(end of broadcast)--------------------------- > TIP 1: subscribe and unsubscribe commands go to majordomo@postgresql.org
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