Re: SQL problem with aggregate functions.

What is wrong with:

select field_group, sum( case when f1 = 'D' then cnt else 0 end) as
D_COUNT, sum( case when f1 = 'R' then cnt else 0 end) as R_COUNT, sum( case when f1 = 'X' then cnt else 0 end) as
X_COUNT
from (select field_group, f1, count (*) as cnt from tab group by
field_group, f1) as ss
group by field_group;

It should be faster because there is less CASE evaluation.


Loyd Goodbar wrote:
> 
> I would suggest something like
> 
> select sum(case when f1 = 'D' then 1 else 0 end) as D_COUNT,
> sum(case when f1 = 'R' then 1 else 0 end) as R_COUNT,
> sum(case when f1 = 'X' then 1 else 0 end) as X_COUNT
> from tab
> where f1 in ('D','R','X')
> 
> Not sure what the "field group" represents.
> 
> HTH,
> Loyd
> 
> On Thu, 11 Jul 2002 10:37:40 METDST, Christoph Haller <ch@rodos.fzk.de> wrote:
> 
> >>
> >> I've got a table in which there is a field that can have one amongst 3
> >> possible values : D, R, X. Is it possible to get in one query the count of
> >> this different values.Please, note that I don't want to have a querry like
> >> this :
> >> "select count (*) from tab group by f1;", cause i want to get all the possible
> >> count values in one row (these data are already grouped on another field).
> >> To give a more accurate example, here is what I want to retrieve :
> >>
> >> Field group | count of D | count of R | count of X.
> >>
> >> Any clues ?
> >> --
> >What about something like
> >
> >
> >SELECT SUM(f1_d) AS count_d,
> >       SUM(f1_r) AS count_r,
> >       SUM(f1_x) AS count_x
> >FROM (
> > SELECT CASE WHEN f1 = 'D' THEN 1 ELSE 0 END AS f1_d,
> >        CASE WHEN f1 = 'R' THEN 1 ELSE 0 END AS f1_r,
> >        CASE WHEN f1 = 'X' THEN 1 ELSE 0 END AS f1_x
> > FROM tab ) AS foo ;
> >
> >Regards, Christoph
> >
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> --
> "Why, you can even hear yourself think." --Hobbes
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