Problems with PL/pgSQL and LIKE statement
От | Paul Murphy |
---|---|
Тема | Problems with PL/pgSQL and LIKE statement |
Дата | |
Msg-id | 3C129FC9A1BC9446921D3D2B2BBEB07612091B@sbs2003.PacketDynamics.local обсуждение исходный текст |
Список | pgsql-novice |
Hi all, I'm writing a function that basically returns all of the URLs that are like (in the SQL sense of LIKE) a string that I supply. I can't seem to get the correct arrangement of percent symbols and quotes to get the statement to run correctly. Here's a simplified version of what I'm trying to do... CREATE OR REPLACE FUNCTION get_urls_like(varchar) RETURNS varchar AS 'DECLARE param ALIAS FOR $1; entry varchar; BEGIN FOR entry IN SELECT url AS url FROM urls u WHERE url LIKE ''''%'''' || param || ''''%'''' LOOP RETURN NEXT entry; END LOOP; RETURN; END;' LANGUAGE 'plpgsql' STABLE; Any help gratefully received. I've tried various combinations of percent signs and single quotes and usually end up with errors like the following. ERROR: operator is not unique: "unknown" % "unknown" HINT: Could not choose a best candidate operator. You may need to add explicit type casts. CONTEXT: PL/pgSQL function "get_classifications_like" line 6 at for over select rows Cheers Paul Paul Murphy Senior Software Engineer Packet Dynamics Ltd tel: +44 (0)1506 426 976 fax: +44 (0)1506 418 844 pmurphy at bloxx dot com Call 08700 4 BLOXX or visit www.bloxx.com
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