Hi,
2013/11/15 0:43、David Johnston <polobo@yahoo.com> のメッセージ:
> bocap wrote
>>>> (rec[1]).t1 := 1;
>
> You need to stay one-level higher and re-build the entire typ entry then
> assign it back to the array at the same position.
>
> rec[1] = (1, rec[1].t2)::typ;
>
Thanks. I think, i can solve it with this way.
> David J.
>
>
>
>
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Regards,
Huong,