Re: [PATCH] GROUP BY ALL
От | Paul Jungwirth |
---|---|
Тема | Re: [PATCH] GROUP BY ALL |
Дата | |
Msg-id | 376ba068-4f12-4ee0-99d8-e19defbb6d29@illuminatedcomputing.com обсуждение исходный текст |
Ответ на | Re: [PATCH] GROUP BY ALL (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-hackers |
On 7/22/24 15:43, Tom Lane wrote: > Isaac Morland <isaac.morland@gmail.com> writes: >> And for when this might be useful, the syntax for it already exists, >> although a spurious error message is generated: > >> odyssey=> select (uw_term).*, count(*) from uw_term group by uw_term; >> ERROR: column "uw_term.term_id" must appear in the GROUP BY clause or be >> used in an aggregate function >> LINE 1: select (uw_term).*, count(*) from uw_term group by uw_term; >> ^ > >> I'm not sure exactly what's going on here > > The SELECT entry is expanded into "uw_term.col1, uw_term.col2, > uw_term.col3, ...", and those single-column Vars don't match the > whole-row Var appearing in the GROUP BY list. I guess if we > think this is important, we could add a proof rule saying that > a per-column Var is functionally dependent on a whole-row Var > of the same relation. Odd that the point hasn't come up before > (though I guess that suggests that few people try this). I was just using this group-by-row feature last week to implement a temporal outer join in a way that would work for arbitrary tables. Here is some example SQL: https://github.com/pjungwir/temporal_ops/blob/b10d65323749faa6c47956db2e8f95441e508fce/sql/outer_join.sql#L48-L66 That does `GROUP BY a` then `SELECT (x.a).*`.[1] It is very useful for writing queries that don't want to know about the structure of the row. I noticed the same error as Isaac. I worked around the problem by wrapping it in a subquery and decomposing the row outside. It's already an obscure feature, and an easy workaround might be why you haven't heard complaints before. I wouldn't mind writing a patch for that rule when I get a chance (if no one else gets to it first.) [1] Actually I see it does `GROUP BY a, a.valid_at`, but that is surely more than I need. I think that `a.valid_at` is leftover from a previous version of the query. Yours, -- Paul ~{:-) pj@illuminatedcomputing.com
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