Re: pg_query won't execute
От | Tom Lane |
---|---|
Тема | Re: pg_query won't execute |
Дата | |
Msg-id | 28648.1520195976@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | pg_query won't execute ("Dale Schmitz" <dschmitz4@cox.net>) |
Список | pgsql-novice |
"Dale Schmitz" <dschmitz4@cox.net> writes: > The statement "SELECT COUNT(*) FROM users WHERE username = 'john' works just > fine in the pgAdmin query tool, but not like this: > $sql = "SELECT COUNT(*) FROM users WHERE username = $username"; What you're presumably ending up with is a query string like SELECT COUNT(*) FROM users WHERE username = john which isn't going to work ... unless there's a column named "john" in "users", and even then it probably doesn't produce the result you intended. You need to quote the inserted value as a literal. But really the better way would be to insert "john" as a parameter. If you do something like this: $sql = "SELECT COUNT(*) FROM users WHERE username = '$username'"; it'd appear to work, until you ran into a username containing a single quote. (You've heard of SQL injection, right?) I don't know PHP, so I'm not sure whether it provides any convenient way to produce a safely escaped literal equivalent of an arbitrary input string. But I'm almost sure it will let you do something along the lines of $sql = "SELECT COUNT(*) FROM users WHERE username = ?"; and then separately transmit the value to be used for the parameter symbol. regards, tom lane
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