Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006
От | Tom Lane |
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Тема | Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006 |
Дата | |
Msg-id | 28203.1583878791@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | BUG #16293: postgres segfaults and returns SQLSTATE 08006 (PG Bug reporting form <noreply@postgresql.org>) |
Ответы |
Re: BUG #16293: postgres segfaults and returns SQLSTATE 08006
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Список | pgsql-bugs |
PG Bug reporting form <noreply@postgresql.org> writes: > I finally found the issue was that one of the tests was trying to insert a > row on a partitioned table, but there was no partition where to put that > row, so it had to go to the default partition. But, the default partition > had a constraint that disallowed that row, so the row couldn't be inserted > and Postgres ended with a segfault. Hm, works for me: regression=# create table tt (f1 int, f2 text) partition by list(f1); CREATE TABLE regression=# create table t1 partition of tt for values in (1); CREATE TABLE regression=# create table tother partition of tt default; CREATE TABLE regression=# alter table tother add check (length(f2) > 1); ALTER TABLE regression=# insert into tt values (1, 'f'); INSERT 0 1 regression=# insert into tt values (3, 'f'); ERROR: new row for relation "tother" violates check constraint "tother_f2_check" DETAIL: Failing row contains (3, f). regression=# Admittedly this is v11 branch tip not exactly 11.7, but I don't see anything related-looking in the commit log. So I think there is some contributing factor you didn't mention. Could you provide a self-contained reproduction script? regards, tom lane
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