Re: SELECT with sum on groups ORDERING by the subtotals

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> I need an subtotal for all the products with the same group and that the
> query be ordered by the bigger subtotal.

(please proofread: the subtotals in your example output did not add up)

By "same group" I presume you mean the same code, as you don't actually use
the "group varchar(10)" column you created in your example. A major problem
you have is that you have no other way of ordering the rows except by the
code. So having a running subtotal is fairly pointless, as the items within
each code will appear randomly. Since only the grand total for each code is
significant, you could write something like this:

SELECT t.*, s.subtotal FROM(SELECT code, SUM(total) AS subtotal FROM test GROUP BY 1) s,test tWHERE s.code =
t.codeORDERBY subtotal desc;
 
code  | description | quant | price | total | subtotal
- -------+-------------+-------+-------+-------+----------99120 | PRODUCT C   |    10 |   0.8 |     8 |      33899120 |
PRODUCTC   |   100 |   0.8 |    80 |      33899120 | PRODUCT C   |   200 |   0.8 |   160 |      33899120 | PRODUCT C
|  100 |   0.9 |    90 |      33892110 | PRODUCT A   |    10 |     1 |    10 |      12092110 | PRODUCT A   |     5 |
0.9|     9 |      12092110 | PRODUCT A   |   100 |   0.9 |    90 |      12092110 | PRODUCT A   |    10 |   1.1 |    11
|     12092190 | PRODUCT b   |    10 |   1.1 |    11 |       4192190 | PRODUCT b   |    10 |   1.1 |    11 |
4192190| PRODUCT b   |    10 |   1.1 |    11 |       4192190 | PRODUCT b   |    20 |   0.8 |     8 |       41
 

If you don't need all that intermediate stuff:

SELECT code, SUM(total) AS subtotal FROM test GROUP BY 1 ORDER BY 2 DESC;
code  | subtotal
- -------+----------99120 |      33892110 |      12092190 |       41

If you do need the other rows, you will have to specify a way of ordering
the rows within a code group.

- --
Greg Sabino Mullane greg@turnstep.com
PGP Key: 0x14964AC8 200506161458
http://biglumber.com/x/web?pk=2529DF6AB8F79407E94445B4BC9B906714964AC8

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