Re: C functions and int8?
От | Tom Lane |
---|---|
Тема | Re: C functions and int8? |
Дата | |
Msg-id | 25782.969588387@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: C functions and int8? (Forest Wilkinson <fspam@home.com>) |
Список | pgsql-sql |
Forest Wilkinson <fspam@home.com> writes: > That's an int8 meaning "eight bit integer". I want to work with an int8 > meaning "64 bit integer", as described in the docs: > http://www.postgresql.org/users-lounge/docs/7.0/user/datatype.htm#AEN942 > So how do I return one of these suckers from a C function? Emulate the code in src/backend/utils/adt/int8.c. Currently this involves palloc'ing an int8, setting it, and returning a pointer to it. For instance, int8 addition is int64 * int8pl(int64 *val1, int64 *val2) { int64 *result = palloc(sizeof(int64)); if ((!PointerIsValid(val1)) || (!PointerIsValid(val2))) return NULL; *result = *val1 + *val2; return result; } In 7.1 it'll be a lot cleaner (IMNSHO anyway ;-)): Datum int8pl(PG_FUNCTION_ARGS) { int64 val1 = PG_GETARG_INT64(0); int64 val2 = PG_GETARG_INT64(1); PG_RETURN_INT64(val1 + val2); } which actually does about the same things under the hood, but you don't have to sully your hands with 'em ... regards, tom lane
В списке pgsql-sql по дате отправления: