Re: order by using functions under unions
От | Tom Lane |
---|---|
Тема | Re: order by using functions under unions |
Дата | |
Msg-id | 25313.989531450@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | order by using functions under unions (pgsql-bugs@postgresql.org) |
Список | pgsql-bugs |
pgsql-bugs@postgresql.org writes: > select name from temp where name like 'e%' > union > select name from temp where name not like 'e%' > order by substr(name,1,4) asc; This isn't supported. 7.1 knows that it can't do it: regression=# select name from temp where name like 'e%' regression-# union regression-# select name from temp where name not like 'e%' regression-# order by substr(name,1,4) asc; ERROR: ORDER BY on a UNION/INTERSECT/EXCEPT result must be on one of the result columns It'd be nice to make it happen for the case you illustrate (ORDER BY on an expression using only result columns) but that's not done yet. In the meantime you can work around it (again, in 7.1) by using an explicit subselect: regression=# select name from ( regression(# select name from temp where name like 'e%' regression(# union regression(# select name from temp where name not like 'e%' regression(# ) ss regression=# order by substr(name,1,4) asc; name --------- chantal daniel eric ernst (4 rows) regards, tom lane
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