Re: tricky GROUP BY / JOIN question
От | Tom Lane |
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Тема | Re: tricky GROUP BY / JOIN question |
Дата | |
Msg-id | 22995.1099852316@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | tricky GROUP BY / JOIN question (T E Schmitz <mailreg@numerixtechnology.de>) |
Ответы |
Re: tricky GROUP BY / JOIN question
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Список | pgsql-sql |
T E Schmitz <mailreg@numerixtechnology.de> writes: > This is *almost* what I need: > SELECT > BRAND.BRAND_NAME, > MODEL.MODEL_NAME, > min (ITEM.PRICE),max (ITEM.PRICE) > *min (CONDITION.POSITION),max (CONDITION.POSITION)* > FROM ITEM > left outer join MODEL on MODEL_PK =ITEM.MODEL_FK > left outer join BRAND on BRAND.BRAND_PK =MODEL.BRAND_FK > left outer join CONDITION on CONDITION.CONDITION_PK = ITEM.CONDITION_FK > group by BRAND.BRAND_NAME,MODEL.MODEL_NAME > In the result I don't want min/max(POSITION) but CONDITION.NAME of min > and max(POSITION) for each MODEL. I think you could do something like SELECT BRAND.BRAND_NAME, MODEL.MODEL_NAME, min (ITEM.PRICE),max (ITEM.PRICE) (select name from condition c1 where position = min(condition.position)), (select name from condition c2 where position = max(condition.position)), FROM ITEM left outer join MODEL on MODEL_PK =ITEM.MODEL_FK left outer join BRAND on BRAND.BRAND_PK =MODEL.BRAND_FK left outer join CONDITION on CONDITION.CONDITION_PK = ITEM.CONDITION_FK group by BRAND.BRAND_NAME,MODEL.MODEL_NAME ie do a sub-select to get the desired name. You need Postgres 7.4 or later to get this to work --- before that we would have mis-interpreted the aggregate calls to indicate aggregation within the sub-selects. The current interpretation is per SQL spec: since the aggregate argument is a variable of the outer select, the aggregation occurs with respect to that select, and the aggregate result is passed down to the sub-select as a scalar. regards, tom lane
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