Re: Counting the number of repeated phrases in a column

On Wed, Jan 26, 2022 at 5:23 PM Merlin Moncure <mmoncure@gmail.com> wrote:

with s as (select 'Hello World Hello World' as sentence)
select  phrase,  array_upper(string_to_array((select sentence from s), phrase), 1) -
1 as occurrances
from
(  select array_to_string(x, ' ') as phrase  from  (    select distinct v[a:b]  x    from regexp_split_to_array((select sentence from s), ' ') v    cross join lateral generate_series(1, array_upper(v, 1)) a    cross join lateral generate_series(a + 1, array_upper(v, 1)) b  ) q
) q;

Simplified to:
select distinct array_to_string(v[a:b], ' ') phrase, count(*) as occurrences
from regexp_split_to_array('Hello World Hello World', ' ') v
cross join lateral generate_series(1, array_upper(v, 1)) a
cross join lateral generate_series(a + 1, array_upper(v, 1)) b
group by 1;
         phrase          │ occurances
─────────────────────────┼──────────── World Hello             │          1 Hello World Hello       │          1 Hello World             │          2 Hello World Hello World │          1 World Hello World       │          1

merlin

having count(*) > 1