Fabien COELHO <coelho@cri.ensmp.fr> writes:
> Maybe something wrong with the regproc type?
regprocout doesn't schema-qualify if the function name is unique without
it.
Of course, the function name isn't necessarily unique *with* it, either,
but regproc can't do anything about that. Cast to regprocedure if you
want to see a more helpful display of the function.
regards, tom lane