Re: BUG #15724: Can't create foreign table as partition
От | Tom Lane |
---|---|
Тема | Re: BUG #15724: Can't create foreign table as partition |
Дата | |
Msg-id | 21389.1553868091@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: BUG #15724: Can't create foreign table as partition (Alvaro Herrera <alvherre@2ndquadrant.com>) |
Ответы |
Re: BUG #15724: Can't create foreign table as partition
Re[2]: BUG #15724: Can't create foreign table as partition |
Список | pgsql-bugs |
Alvaro Herrera <alvherre@2ndquadrant.com> writes: > On 2019-Mar-29, PG Bug reporting form wrote: >> SQL Error [42809]: ERROR: cannot create index on foreign table "msg_json" > Ah, this is because we try to propagate the index to the partition, > which appears to be less than desirable. Maybe this patch fixes it? I > have not tested it, only verified that it compiles. Really, what *ought* to happen in such a case is that the FDW gets told about the command and has the opportunity to try to do something corresponding to making an index. But that smells like a new feature rather than a bug fix. I'm not sure that just forcing the case to be a no-op is wise. What if the index is supposed to be UNIQUE? regards, tom lane
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