Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock
От | Alvaro Herrera |
---|---|
Тема | Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock |
Дата | |
Msg-id | 20190615224713.GA9414@alvherre.pgsql обсуждение исходный текст |
Ответ на | Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock (Oleksii Kliukin <alexk@hintbits.com>) |
Ответы |
Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock
Re: pgsql: Avoid spurious deadlocks when upgrading a tuple lock |
Список | pgsql-hackers |
On 2019-Jun-16, Oleksii Kliukin wrote: > Alvaro Herrera <alvherre@2ndquadrant.com> wrote: > > > On 2019-Jun-14, Alvaro Herrera wrote: > > > >> I think there are worse problems here. I tried the attached isolation > >> spec. Note that the only difference in the two permutations is that s0 > >> finishes earlier in one than the other; yet the first one works fine and > >> the second one hangs until killed by the 180s timeout. (s3 isn't > >> released for a reason I'm not sure I understand.) > > > > Actually, those behaviors both seem correct to me now that I look > > closer. So this was a false alarm. In the code before de87a084c0, the > > first permutation deadlocks, and the second permutation hangs. The only > > behavior change is that the first one no longer deadlocks, which is the > > desired change. > > > > I'm still trying to form a case to exercise the case of skip_tuple_lock > > having the wrong lifetime. > > Hm… I think it was an oversight from my part not to give skip_lock_tuple the > same lifetime as have_tuple_lock or first_time (also initializing it to > false at the same time). Even if now it might not break anything in an > obvious way, a backward jump to l3 label will leave skip_lock_tuple > uninitialized, making it very dangerous for any future code that will rely > on its value. But that's not the danger ... with the current coding, it's initialized to false every time through that block; that means the tuple lock will never be skipped if we jump back to l3. So the danger is that the first iteration sets the variable, then jumps back; second iteration initializes the variable again, so instead of skipping the lock, it takes it, causing a spurious deadlock. -- Álvaro Herrera https://www.2ndQuadrant.com/ PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services
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