Re: pgsql: Allow UNIQUE indexes on partitioned tables
От | Alvaro Herrera |
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Тема | Re: pgsql: Allow UNIQUE indexes on partitioned tables |
Дата | |
Msg-id | 20180220153647.blzfw7u47ykjkdsc@alvherre.pgsql обсуждение исходный текст |
Ответ на | Re: pgsql: Allow UNIQUE indexes on partitioned tables ("David G. Johnston" <david.g.johnston@gmail.com>) |
Ответы |
Re: pgsql: Allow UNIQUE indexes on partitioned tables
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Список | pgsql-hackers |
Many thanks for reading through it! David G. Johnston wrote: > I found the following change to be confusing. [...] > I was expecting the doc for ADD CONSTRAINT USING INDEX to note the > limitation explicitly - in lieu of the above paragraph. Agreed. I moved the note to ADD CONSTRAINT and added a different on to ADD CONSTRAINT USING INDEX. > Also, I cannot reason out what the following limitation means: > > /doc/src/sgml/ref/create_table.sgml > + If any partitions are in turn partitioned, all columns of each > partition > + key are considered at each level below the <literal>UNIQUE</literal> > + constraint. I can see that being unclear. I tried to be very concise, to avoid spending too many words on what is mostly a fringe feature; but that probably didn't work very well. Wording suggestions welcome. What this means is that if you create a partition that is partitioned on a column different from its parent, then a primary key that covers the whole hierarchy (i.e. you're not just adding a PK to the partitioned partition) must include all partition columns, not just the upper one. Example: create table t (a int, b int) partition by range (a); create table t_1 partition of t for values from (0) to (1000) partition by range (b); then you may create a unique or PK constraint on t only if you include both columns (a,b). You may not create a PK on t (a), which is a bit surprising since (b) is not part of the partition key of t directly, only of t_1. Of course, if you create a unique constraint on t_1 (i.e. it doesn't cover all of t) then you may use (b) alone -- that's what "each level below the UNIQUE constraint" supposed to convey. I have trouble coming up with a real-world example where you would run into this limitation in practice. -- Álvaro Herrera https://www.2ndQuadrant.com/ PostgreSQL Development, 24x7 Support, Remote DBA, Training & Services
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