Re: Unexpected interval comparison
От | Kyotaro HORIGUCHI |
---|---|
Тема | Re: Unexpected interval comparison |
Дата | |
Msg-id | 20170404.171503.228263525.horiguchi.kyotaro@lab.ntt.co.jp обсуждение исходный текст |
Ответ на | Re: Unexpected interval comparison (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-general |
Thank you for the comment. At Mon, 03 Apr 2017 11:35:25 -0400, Tom Lane <tgl@sss.pgh.pa.us> wrote in <23053.1491233725@sss.pgh.pa.us> > Kyotaro HORIGUCHI <horiguchi.kyotaro@lab.ntt.co.jp> writes: > > Ok, the attached patch changes the result type of > > interval_cmp_value from TimeOffset(=int64) to new 128 bit > > LinearInterval. The value is hidden under the functions > > interval_eq/ge.../cmp and all other stuff seems to use the > > functions. > > Looking at this now ... why isn't the INT64_AU32 macro just > > #define INT64_AU32(i64) ((i64) >> 32) > > ? The business with subtracting and re-adding 1 seems unnecessary, and it > also creates a risk of overflow with the minimum possible int64 value. It is equivalent to "i64 / (1<<32)" except for -INT64_MAX. INT64_AU32 gives the value for the first term in the following polynomial. (int64)INT64_AU32(i64) * (2^32) + (int64)INT64_AL32(i64) = i64 The previous expression intended to avoid decimal arithmetic, but gcc optimizes the simple division better (using cmovns-add-sar) than the current INT64_AU32 (jmp-sar) so I changed it. This doesn't suffer overflow. -#define INT64_AU32(i64) (((i64) < 0 ? (((i64) - 1) >> 32) + 1: ((i64) >> 32))) +#define INT64_AU32(i64) ((i64) / (1LL<<32)) In summation of terms in 128bit multiplication expression, I noticed that the value of the second term's lower 32bit loses MSB for certain cases. I changed LINEARINTERVAL_ADD_INT64 to accept the MSB (as the 65th bit) separately. The first attached is the revised patch and the second is temporary sanity check code for non-128bit environment code. (but works only on 128 bit environment) regards, -- Kyotaro Horiguchi NTT Open Source Software Center
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