Re: [HACKERS] Idea on how to simplify comparing two sets
От | David Fetter |
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Тема | Re: [HACKERS] Idea on how to simplify comparing two sets |
Дата | |
Msg-id | 20170207171017.GB11993@fetter.org обсуждение исходный текст |
Ответ на | [HACKERS] Idea on how to simplify comparing two sets (Joel Jacobson <joel@trustly.com>) |
Ответы |
Re: [HACKERS] Idea on how to simplify comparing two sets
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Список | pgsql-hackers |
On Tue, Feb 07, 2017 at 04:13:40PM +0100, Joel Jacobson wrote: > Hi hackers, > > Currently there is no simple way to check if two sets are equal. Assuming that a and b each has at least one NOT NULL column, is this simple enough? Based on nothing much, I'm assuming here that the IS NOT NULL test is faster than IS NULL, but you can flip that and change the array to {0} with identical effect. WITH t AS ( SELECT a AS a, b AS b, (a IS NOT NULL)::int + (b IS NOT NULL)::int AS ind FROM a FULL JOIN b ON ... ) SELECT array_agg(DISTINCT ind) = '{2}' FROM t; Best, David. -- David Fetter <david(at)fetter(dot)org> http://fetter.org/ Phone: +1 415 235 3778 AIM: dfetter666 Yahoo!: dfetter Skype: davidfetter XMPP: david(dot)fetter(at)gmail(dot)com Remember to vote! Consider donating to Postgres: http://www.postgresql.org/about/donate
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