Re: sum an alias

In response to Wes James :
> In the statement:
> 
> select
>     MAX(page_count_count) - MIN(page_count_count) as day_tot,
>     MAX(page_count_count) as day_max, sum(MAX(page_count_count) -
> MIN(page_count_count)) as tot,
>     page_count_pdate
> from page_count
> group by page_count_pdate order by page_count_pdate
> 
> Is there a way to do sum(day_tot) also in the same statement?

Is this the correct table-definition?

test=# \d page_count      Table "public.page_count"     Column      |  Type   | Modifiers
------------------+---------+-----------page_count_pdate | date    |page_count_count | integer |


If yes, your SQL is wrong:

test=# select   MAX(page_count_count) - MIN(page_count_count) as day_tot,   MAX(page_count_count) as day_max,
sum(MAX(page_count_count)-
 
MIN(page_count_count)) as tot,   page_count_pdate
from page_count
group by page_count_pdate order by page_count_pdate;
ERROR:  aggregate function calls cannot be nested
LINE 3:     MAX(page_count_count) as day_max, sum(MAX(page_count_cou...


Can you provide the correct table definition?

Regards, Andreas
-- 
Andreas Kretschmer
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