Re: right join problem
От | A. Kretschmer |
---|---|
Тема | Re: right join problem |
Дата | |
Msg-id | 20091002054548.GB22496@a-kretschmer.de обсуждение исходный текст |
Ответ на | right join problem (Greenhorn <user.postgresql@gmail.com>) |
Список | pgsql-sql |
In response to Greenhorn : > Hi, > > I'm trying to retrieve all meter_id from table meter, and for meter_id > without amount, I'd like it to show nothing, 'null'. I've used right > join here but it's not giving me my desired result. Is there another > way to do this? Here's the query I'm trying. > > Thanks in advance! > > select m.meter_id, mp.meter_id, sum(amount_in_cents) as am > from meter m > right join transaction_mpark mp on (m.meter_id = mp.meter_id) > where date_time between '2009-09-28 00:00:00' and '2009-10-04 23:59:59' > group by m.meter_id, mp.meter_id > order by m.meter_id Use a left join instead? test=*# select * from master;id | name ----+---------- 1 | master 1 2 | master 2 (2 rows) test=*# select * from slave;id | value ----+------- 1 | 1 1 | 2 1 | 3 (3 rows) test=*# select m.id, s.id, sum(s.value) from master m right join slave s on (m.id=s.id) group by m.id, s.id;id | id | sum ----+----+----- 1 | 1 | 6 (1 row) test=*# select m.id, s.id, sum(s.value) from master m left join slave s on (m.id=s.id) group by m.id, s.id;id | id | sum ----+----+----- 1 | 1 | 6 2 | | (2 rows) Andreas -- Andreas Kretschmer Kontakt: Heynitz: 035242/47150, D1: 0160/7141639 (mehr: -> Header)
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