mysql code questions
От | Ray Stell |
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Тема | mysql code questions |
Дата | |
Msg-id | 20090812181928.GF7527@cns.vt.edu обсуждение исходный текст |
Ответы |
Re: mysql code questions
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Список | pgsql-sql |
http://www.brentozar.com/archive/2009/04/getting-the-most-recent-record/ How this works? What is ttNewer? What is a clustered primary key in mysql? This is as good as I can do to get this into pg: create table TestTable (id int not null,create_date date not null,info1 VARCHAR(50) NOT NULL,info2 VARCHAR(50) NOT NULL,constraintPK_TestTable PRIMARY KEY(id,create_date) ); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (1, '1/1/09', 'Blue', 'Green'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (1, '1/2/09', 'Red', 'Yellow'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (1, '1/3/09', 'Orange', 'Purple'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (2, '1/1/09', 'Yellow', 'Blue'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (2, '1/5/09', 'Blue', 'Orange'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (3, '1/2/09', 'Green', 'Purple'); INSERT INTO TestTable (id, create_date, info1, info2) VALUES (3, '1/8/09', 'Red', 'Blue'); select tt.* FROM TestTable tt LEFT OUTER JOIN TestTable ttNewer ON tt.id = ttNewer.id AND tt.create_date < ttNewer.create_dateWHERE ttNewer.id IS NULL; id | create_date | info1 | info2 ----+-------------+--------+-------- 1 | 2009-01-03 | Orange | Purple 2 | 2009-01-05 | Blue | Orange 3 | 2009-01-08 | Red | Blue (3 rows)
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