Re: Doubt about join clause
От | Sam Mason |
---|---|
Тема | Re: Doubt about join clause |
Дата | |
Msg-id | 20090421011358.GH12225@frubble.xen.chris-lamb.co.uk обсуждение исходный текст |
Ответ на | Re: Doubt about join clause (David Wilson <david.t.wilson@gmail.com>) |
Список | pgsql-general |
On Mon, Apr 20, 2009 at 08:02:49PM -0400, David Wilson wrote: > On Mon, Apr 20, 2009 at 7:39 PM, jc_mich <juan.michaca@paasel.com> wrote: > > You've understood very well my problem, but also this query works as worse > > than everything I did before, it throws as many rows as rows are contained > > my tables clients and stores. I only want to find for every client what > > store is closer to him, I expect one client to one store and their distance > > select clients.id as client_id, (select stores.id from stores order by > (power(clients.x-stores.x)+power(clients.y-stores.y)) asc limit 1) as > store_id from clients; > > Should do the trick, or at least something very similar. Another option would be to use DISTINCT ON and the geometric bits in PG, something like: SELECT DISTINCT ON (client_id) client_id, store_id, distance FROM ( SELECT c.id AS client_id, s.id AS store_id, point(c.x,c.y) <-> point(s.x,s.y) AS distance FROM clients c, stores s) ORDER BY client_id, distance; I'd also expect there to be some GiST magic that can be weaved to get the above to work somewhat efficiently. -- Sam http://samason.me.uk/
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