Re: Doing a conditional aggregate (e.g. count(*) if x=y) in postgres?

Use case statement and sum to get a count where status=20...

For example

Select sum(case when status=20 then 1 else 0 end) as status20,      Sum(case when status=30 then 1 else 0 end) as
status30
....


-----Original Message-----
From: pgsql-sql-owner@postgresql.org [mailto:pgsql-sql-owner@postgresql.org]
On Behalf Of Bryce Nesbitt
Sent: Monday, May 14, 2007 6:56 PM
To: pgsql-sql@postgresql.org
Subject: [SQL] Doing a conditional aggregate (e.g. count(*) if x=y) in
postgres?

All;
Is there a way to get a conditional aggregate?  I have this two column view:
SELECT count(*) AS count, xx_plan.plan_name  FROM xx_membership  JOIN xx_account USING (account_id)  JOIN xx_plan USING
(plan_id)WHERE xx_membership.status = 10 GROUP BY xx_plan.plan_name;
 

And would like to add additional columns (not rows) breaking out
"status=20" and "status=30" totals.
Is this possible without a stored procedure?


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