Re: interval as hours or minutes ?
От | Aarni Ruuhimäki |
---|---|
Тема | Re: interval as hours or minutes ? |
Дата | |
Msg-id | 200702081317.57255.aarni@kymi.com обсуждение исходный текст |
Ответ на | Re: interval as hours or minutes ? ("Bart Degryse" <Bart.Degryse@indicator.be>) |
Список | pgsql-sql |
Ahh, Forgot about trunc() in the midst of all this ... Thank you guys again ! Aarni On Thursday 08 February 2007 12:06, Bart Degryse wrote: > Use trunc instead of round. > Also take a look at ceil and floor functions > > >>> Aarni Ruuhimäki <aarni@kymi.com> 2007-02-08 11:01 >>> > > On Thursday 08 February 2007 00:09, you wrote: > > select extract(epoch from (timestamp '2007-02-07 16:24:00' - > > timestamp > > > '2007-02-05 13:00:01'))/60 as minutes; > > > > minutes > > ------------------ > > 3083.98333333333 > > (1 row) > > > > select round(extract(epoch from (timestamp '2007-02-07 16:24:00' - > > timestamp '2007-02-05 13:00:01'))/60) as minutes; > > > > minutes > > --------- > > 3084 > > (1 row) > > Hi Guys, > > Charming ! > > Furher still, I would only want full minutes. > > select extract(epoch from (SELECT SUM(stop_date_time - start_date_time) > FROM > work_times WHERE user_id = 10 AND start_date_time >= '2007-01-01' AND > stop_date_time <= '2007-02-28')/60) as mins; > mins > ------------- > 3728.733333 > (1 row) > > select convert_interval((SELECT SUM(stop_date_time - start_date_time) > FROM > work_times WHERE user_id = 10 AND start_date_time >= '2007-01-01' AND > stop_date_time <= '2007-02-28'),'minutes') as minutes; > minutes > -------------------------- > 3728.73333333333 minutes > (1 row) > > select round(extract(epoch from (SELECT SUM(stop_date_time - > start_date_time) > FROM work_times WHERE user_id = 10))/60) as mins; > mins > ------ > 3729 > (1 row) > > So instead of rounding up to 3729 the result would have to be > 'stripped' to > 3728 ? > > Thanks,
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