Re: BUG #2889: Syntax error: WHERE ANY(arrayfield) = N

David Higgs wrote:
> On 1/13/07, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> > "David" <higgsd@gmail.com> writes:
> > > This statement works:
> > > => SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
> >
> > > But this does not:
> > > => SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
> > > ERROR:  syntax error at or near "ANY" at character ...
> >
> > This is not a bug, it's the way the syntax works per SQL spec.
> > ANY must immediately follow the operator it relates to.  See
> > <quantified comparison predicate> syntax in the spec.
> >
> >                         regards, tom lane
> >
>
> Aha, I see it in the docs now, although it's still rather unintuitive.
>  Could the appropriate section on arrays be crosslinked to the ANY/ALL
> page, to preempt this question in the future?

I researched this and found this line right above the example you quoted
above:

    An alternative method is described in Section 9.17. The above query
    could be replaced by:

    SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);

and section 9.17 is 9.17. Row and Array Comparisons.  Not sure we can do
any better than that.

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  Bruce Momjian   bruce@momjian.us
  EnterpriseDB    http://www.enterprisedb.com

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