Re: Grouping aggregate functions
От | Martijn van Oosterhout |
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Тема | Re: Grouping aggregate functions |
Дата | |
Msg-id | 20060402115130.GA1298@svana.org обсуждение исходный текст |
Ответ на | Grouping aggregate functions (Richard Connamacher <rich.n1@indieimage.com>) |
Ответы |
Re: Grouping aggregate functions
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Список | pgsql-general |
On Sun, Apr 02, 2006 at 04:03:03AM -0700, Richard Connamacher wrote: > I've got a question, if anyone can help me out. I know how to use an > aggregate function to, say, find the lowest price ever listed for a > product. I also know how to combine that with a SELECT ... GROUP BY > statement to find, say, the lowest price reported for each month. > Now, what if I want to find the *average* of all the lowest prices > for each month? Plopping that SELECT statement inside parentheses and > inside an "avg( )" function produces an error. Use a subquery. ie.e not: > SELECT avg( ( SELECT min(price) FROM weekly_supply_prices GROUP BY > month ) ) But SELECT avg(minprice) FROM (SELECT min(price) as minprice FROM weekly_supply_prices GROUP BY month ); > Anyone have any idea how to do this? Or do I have to compute the > average in another program? Use SQL to calculate both :) One way to think about it is by think of the subquery producing a temporary table which you then use in another query. Have a nice day, -- Martijn van Oosterhout <kleptog@svana.org> http://svana.org/kleptog/ > Patent. n. Genius is 5% inspiration and 95% perspiration. A patent is a > tool for doing 5% of the work and then sitting around waiting for someone > else to do the other 95% so you can sue them.
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