Re: need help on writing an aggregate function
От | Bruno Wolff III |
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Тема | Re: need help on writing an aggregate function |
Дата | |
Msg-id | 20041116212144.GA30906@wolff.to обсуждение исходный текст |
Ответ на | need help on writing an aggregate function (subhash@nmsu.edu) |
Ответы |
Re: need help on writing an aggregate function
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Список | pgsql-hackers |
On Tue, Nov 16, 2004 at 12:41:45 -0700, subhash@nmsu.edu wrote: > hi, > I was writing my own data type, and, I have to write aggregare function like > min() and max() for my datatype. I googled for the user defined aggregate > functions, but I could not find any examples for the sfunc and ffunc. > Can any of you provide me the source/structure in C or SQL for these two > functions of min or max or avg etc? for a complex type as given in the examples. > Thanks, > subhash. Here is an example I did to do concatenation: drop view people_with_email; drop table people2email; drop table email; drop table people; drop aggregate concatenate(text); drop function join_with_comma(text,text); create function join_with_comma(text,text) returns text immutable strict language 'sql' as 'select $1||'', ''||$2' ; create aggregate concatenate ( sfunc = join_with_comma, basetype = text, stype = text ); create table email ( email_id integer primary key, email_address text not null unique ); copy email from stdin with delimiter '|'; 1|scott@scottg.tv 2|fred.flintstone@blah.com 3|barney@hodown.com 4|barney.rubble@hey.org \. create table people ( person_id integer primary key, first_name text not null, last_name text notnull ); copy people from stdin with delimiter '|'; 1|Scott|Goodwin 2|Fred|Flintstone 3|Barney|Rubble \. create table people2email ( person_id integer references people (person_id), email_id integer referencesemail (email_id) ); copy people2email from stdin with delimiter '|'; 1|1 2|2 3|3 3|4 \. create view people_with_email as select a.first_name, a.last_name, c.email_address from people a, (select r.person_id, concatenate(b.email_address) as email_address from people2email r, email b wherer.email_id = b.email_id group by r.person_id) as c where a.person_id = c.person_id ;
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