Re: Function to convert bigint to date
От | Steven Klassen |
---|---|
Тема | Re: Function to convert bigint to date |
Дата | |
Msg-id | 20041026034636.GA23780@commandprompt.com обсуждение исходный текст |
Ответ на | Re: Function to convert bigint to date ("Pradeepkumar, Pyatalo (IE10)" <Pradeepkumar.Pyatalo@honeywell.com>) |
Список | pgsql-novice |
* Pradeepkumar, Pyatalo (IE10) <Pradeepkumar.Pyatalo@honeywell.com> [2004-10-25 02:23:19 -0700]: > But from the result I need to display only the date and not the > time. Should I use extract() function to get the day, month and year > seperately and then form the date format, or is there any other way > to extract only the date part from the timestamp. You can cast a timestamp to a date. You really need to give these things a try yourself. You'd be surprised what you can figure out through trial and error. xinu=> select now()::timestamp; now ---------------------------- 2004-10-25 23:45:38.939148 (1 row) xinu=> select (now()::timestamp)::date; now ------------ 2004-10-25 (1 row) -- Steven Klassen - Lead Programmer Command Prompt, Inc. - http://www.commandprompt.com/ PostgreSQL Replication & Support Services, (503) 667-4564
В списке pgsql-novice по дате отправления: