Re: Obtaining the Julian Day from a date
От | Bruno Wolff III |
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Тема | Re: Obtaining the Julian Day from a date |
Дата | |
Msg-id | 20040909191106.GA30916@wolff.to обсуждение исходный текст |
Ответ на | Obtaining the Julian Day from a date ("Karl O. Pinc" <kop@meme.com>) |
Список | pgsql-general |
On Thu, Sep 09, 2004 at 12:35:14 -0500, "Karl O. Pinc" <kop@meme.com> wrote: > Hi, > > What's the best way to obtain the Julian day from a postgresql > date? > > PostgreSQL 7.3.4 on i386-redhat-linux-gnu, compiled by GCC > i386-redhat-linux-gcc (GCC) 3.2.2 20030222 (Red Hat Linux 3.2.2-5) > > I'm doing some date arithmetic with 1 day intervals and want > to, for example, round to the even Julian day. I suppose > I could always take the interval from julian day zero > and then divide by the number of seconds in a day, but that > sounds both brutal and potentially inaccurate due to leap > seconds and so forth. > > There's mention of being able to do this in the list archives, > but nobody says how it's actually done. You might be interested to know that there are operators that combine date and integer types that might be usable directly instead of converting to Julian days.
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