Re: Problem in age on a dates interval

On Mon, Jul 19, 2004 at 10:00:50AM +0100, Luis Sousa wrote:
> I worked around this problem returning the difference between the two 
> dates, using extract doy from both.
> Anyway, this will cause a bug on my code when changing the year. Any ideas?

Why don't you use the minus operator?

SELECT '2004-05-14 16:00'::timestamp - '2004-02-18 16:00'::timestamp;?column?
----------86 days

Or, if you need the age just in days:

SELECT extract(day from '2004-05-14 16:00'::timestamp - '2004-02-18 16:00'::timestamp);date_part
-----------       86

or

SELECT '2004-05-14 16:00'::date - '2004-02-18 16:00'::date;?column?
----------      86

Note that '2004-05-14 16:00'::date is actually '2004-05-14 00:00'::date,
so the last two are not always equal.


> Tom Lane wrote:
> 
> >Theodore Petrosky <tedpet5@yahoo.com> writes:
> > 
> >
> >>wow.... at first I thought I had my head around a leap
> >>year problem so I advanced your query a year....
> >>   
> >>
> >
> >I think what's going on here is a difference of interpretation about
> >whether an "M months D days" interval means to add the months first
> >or the days first.  For instance
> >
> >2005-02-18 plus 2 months = 2005-04-18, plus 24 days = 2005-05-12
> >
> >2005-02-18 plus 24 days = 2005-03-14, plus 2 months = 2005-05-14
> >
> >The timestamp-plus-interval operator is evidently doing addition the
> >first way, but it looks like age() is calculating the difference in a
> >way that implicitly corresponds to the second way.
> >
> >I have some vague recollection that this has come up before, but
> >I don't recall whether we concluded that age() needs to be changed
> >or not.  In any case it's not risen to the top of anyone's to-do list,
> >because I see that age() still acts this way in CVS tip.
> >
> >            regards, tom lane

-- 
Fduch M. Pravking