Re: Table alias fun == incorrectly adding tables to join...
От | Stephan Szabo |
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Тема | Re: Table alias fun == incorrectly adding tables to join... |
Дата | |
Msg-id | 20030922140000.D9627@megazone.bigpanda.com обсуждение исходный текст |
Ответ на | Re: Table alias fun == incorrectly adding tables to join... (Sean Chittenden <sean@chittenden.org>) |
Список | pgsql-bugs |
On Mon, 22 Sep 2003, Sean Chittenden wrote: > > > Here's a fun one. > > > > > > test=# CREATE TABLE table_s1 (i int); > > > test=# CREATE TABLE table_s2 (j int); > > > test=# EXPLAIN ANALYZE SELECT table_s1.i, table_s2.j FROM table_s1 AS s1, table_s2 AS s2 WHERE s1.i = s2.j; > > > NOTICE: adding missing FROM-clause entry for table "table_s1" > > > NOTICE: adding missing FROM-clause entry for table "table_s2" > > > QUERY PLAN > > > --------------------------------------------------------------------------------------------------------------------- > > > Nested Loop (cost=0.00..0.03 rows=1 width=8) (actual time=0.03..0.03 rows=0 loops=1) > > > -> Nested Loop (cost=0.00..0.02 rows=1 width=4) (actual time=0.02..0.02 rows=0 loops=1) > > > -> Nested Loop (cost=0.00..0.01 rows=1 width=0) (actual time=0.01..0.01 rows=0 loops=1) > > > Join Filter: ("outer".i = "inner".j) > > > -> Seq Scan on table_s1 s1 (cost=0.00..0.00 rows=1 width=4) (actual time=0.01..0.01 rows=0 loops=1) > > > -> Seq Scan on table_s2 s2 (cost=0.00..0.00 rows=1 width=4) (never executed) > > > -> Seq Scan on table_s1 (cost=0.00..0.00 rows=1 width=4) (never executed) > > > -> Seq Scan on table_s2 (cost=0.00..0.00 rows=1 width=4) (never executed) > > > Total runtime: 0.20 msec > > > (9 rows) > > > > > > If there's real data in the tables, this joins the tables on itself > > > and execution times explode, naturally. I don't know if the spec says > > > this is the correct behavior or not, but I have a feeling its not and > > > this is a bug. -sc > > > > Well, the query is technically invalid I think. > > I'm not 100% sure what the definition of invalid is... If I turn off > add_missing_from, it still fails. ex: > > test=# EXPLAIN ANALYZE SELECT table_s1.i, table_s2.j FROM table_s1 AS s1, table_s2 AS s2 WHERE s1.i = s2.j; > ERROR: missing FROM-clause entry for table "table_s1" > > I know the docs say, "When an alias is provided, it completely hides > the actual name of the table or function; for example given FROM foo > AS f, the remainder of the SELECT must refer to this FROM item as f > not foo." It just struck me as a strange behavior. That's AFAIK the required behavior for SQL (that a table alias hides the other name for the table) and thus for SQL the query would be malformed and violate some grammar or syntax rule when it tries to alias a name that doesn't exist (because table_s1.i or table_s2.j don't resolve to something out of the FROM list).
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