Re: help yourself by helping others
От | Michael A Nachbaur |
---|---|
Тема | Re: help yourself by helping others |
Дата | |
Msg-id | 200307101300.43414.mike@nachbaur.com обсуждение исходный текст |
Ответ на | help yourself by helping others ("Ali Adams" <aliadams@doit4u.com>) |
Список | pgsql-sql |
On Friday 04 April 2003 03:10 am, Ali Adams wrote: > Dear All, > > I am new to Relational Databases and SQL and my background in ODBs is > clouding my way to solving what seems to be a simple problem. I am sure > many of you have met it many times. <snip> Assuming you can have multiple records per day per machine (e.g. you're polling for information throughout the day), the following holds. However, the output doesn't provide for a separate column per day, but rather you get a separate row for each day/machine combination. Attached is a file that demonstrates the behavior I think you would like. But basically, here is the SQL statement you're looking for: SELECT Datestamp, Machine, SUM(Withdrawls) FROM WithdrawlsTable GROUP BY Machine, Datestamp ORDER BY Datestamp, Machine; -- /* Michael A. Nachbaur <mike@nachbaur.com>* http://nachbaur.com/pgpkey.asc*/ "A thought seemed to strike the woman. It struck her very slowly. You could watch it coming in like a long wave on a sandy beach."
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